A rectangle with area 80 square inches has a length that is four less than four times the width

length=16 inches

width = 5 inches

Step-by-step explanation:

Area=l*w=80 square inches

l*w=80 (equation 1)

l=4w-4 (equation 2)

Putting value of l from equation 2 in equation 1

(4w-4) w=80

4w^2-4w-80=0 (equation 3)

Taking 4 common from equation

4 (w^2-w-20) = 0

w^2-w-20=0

w^2-5w+4w-20=0

w (w-5) + 4 (w-5) = 0

(w+4) (w-5) = 0

w=-4, w=5

ignoring the negtive width

we'll solve with w=5 by putting it in equation 2

l = (4*5) - 4

l=20-4

l=16