Find two mixed numbers so that the sum is 21 1/6 and the difference is 4 3/6

Question

Trevin Phelps

Mathematics

31 January, 02:55

Find two mixed numbers so that the sum is 21 1/6 and the difference is 4 3/6

+4

Answers (1)

Know the Answer?

Karlee Stout · Answer 1

A + b = 21 1/6 - - > b = 21 1/6 - a

a - b = 4 3/6

a - (21 1/6 - a) = 4 3/6

a - 21 1/6 + a = 4 3/6

2a = 21 1/6 + 4 3/6

2a = 25 4/6

2a = 154/6

a = (154/6) / 2

a = (154/6) * (1/2)

a = 154/12

a = 12 10/12

a = 12 5/6

b = 21 1/6 - a

b = 21 1/6 - 12 5/6

b = 20 7/6 - 12 5/6

b = 8 2/6

Answer:

a = 12 5/6

b = 8 2/6

Double check:

a + b = 12 5/6 + 8 2/6

a + b = 20 7/6 ... (7/6 = 6/6 + 1/6)

a + b = 21 1/6

a - b = 12 5/6 - 8 2/6

a - b = 4 3/6