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26 July, 21:09

a phone company offers two monthly charge, in Plan a, the customer pays a monthly fee of $40.10 and then an additional 4 cents per minute of use. In plan b, the Customer pays a monthly fee of $35 and then an additional 7 cents per minute of use. for what amounts of monthly phone use will plan a cost no more than Plan B

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  1. 26 July, 21:32
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    x > 1.7 minutes

    The monthly telephone usage amounts so that plan A is not greater than plan B are all greater than 1.7 minutes.

    Step-by-step explanation:

    The two plans must be defined by the equation of the line y = mx + b, where

    y = plan

    m = slope or payment of additional cents per minute

    x = time expressed in minutes

    For Plan A, we have

    y = 4x + 40.10 (Equation A)

    While plan B is defined as

    y = 7x + 35 (Equation B)

    Plan A must be less than Plan B,

    4x + 40.10 < 7x + 35

    We put the "x" on the left side and the independent terms on the right side,

    4x - 7x < 35 - 40.10

    We add algebraically,

    -3x < - 5.10

    We multiply the equation by - 1 to eliminate the two "minus" signs, changing the inequality sign,

    3x > 5.10

    We isolate x,

    x > 5.10 / 3

    We solve, calculating the value of x,

    x > 1.7 minutes

    The monthly telephone usage amounts so that plan A is not greater than plan B are all greater than 1.7 minutes.
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