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Kaylah Anderson
Mathematics
17 March, 06:28
2sin^ (-2490) + tan 1410
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Ella Merritt
17 March, 06:46
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2sin² (-2490) + tan 1410=2sin² (-330-6*360) + tan (330+3*360) =
=2sin² (-330) + tan (330) = 2 sin² (30-1*360) + tan (-30) =
=2sin² (30) - tan (30) = 2 (1/2) ²-√3/3=1/2-√3/3) = (3-2√3) / 6
Answer: 2 sin² (-2490) + tan (1410) = (3-2√3) / 6 (≈-0.07735 ...)
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