Which is a factor of x2 + 8x - 48?

This trinomial factored is:

(x + 12) (x - 4)

either of these would be considered a factor.

So x^2+8x-48

it can be written in the form

ax^2+bx+c

so since the 'a' term=1 we want it in form

(x + / - something1) (x + / - something2)

so basically, something1 times something 2=c and something 1+something 2=b

c=-48

b=8

factor - 48 and fiind what 2 factors add to 8 (obviously one has to be positive and is 8 more than the negative [negative is smaller])

-48=

-1 times 48 no

-2 times 24 no

-3 times 16 no

-4 times 12 yes

-4+12=8

therefor it is

(x-4) (x+12) or (x+12) (x-4)

so the answer would be the one with either (x+12) or (x-4) (since you didn't include answer choices)

(x+12) or (x-4) would be the right choice