After years of maintaining a steady population of 32,000, the population of a town begins to grow exponentially. After 1 year and an increase of 8% per year, the population is 34,560. Which equation can be used to predict, y, the number of people living in the town after x years? (Round population values to the nearest whole number.)

Question

Amari Schaefer

Mathematics

18 October, 01:16

After years of maintaining a steady population of 32,000, the population of a town begins to grow exponentially. After 1 year and an increase of 8% per year, the population is 34,560. Which equation can be used to predict, y, the number of people living in the town after x years? (Round population values to the nearest whole number.)

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Answers (2)

Know the Answer?

Frida Ramirez · Answer 1

A) on Edge2020

Step-by-step explanation:

y = 32,000 (1.08) x

Odin Howard · Answer 2

The equation used to predict the number of people living in the town after x years is y = 32,000 (1.08) x

Step-by-step explanation:

Hi, to answer this question we have to analyze the information given:

Initial population: 32,000 Growth per year: 8% Years: x

So, to obtain "y" (the number of people living in the town after x years), we have to multiply the initial population by 1 + 0.08 (the growth rate is 8%/100=0.08 and the original value) and the number of years (x).

Mathematically speaking:

y = 32,000 (1+0.08) x

y = 32,000 (1.08) x

The equation used to predict the number of people living in the town after x years is y = 32,000 (1.08) x