How many real zeros does y = (x-8) ^3 + 12 have?

To get the zeroes, we will equate the given equation with zero and solve for x as follows:

(x-8) ^3 + 12 = 0

(x-8) ^3 = - 12

x-8 = ∛-12

x - 8 ≈ - 2.2894

x ≈ - 2.2894 + 8

x ≈ 5.71

Based on the above, this equation has only one real zero