How do i solve a quadratic equation like this

Solve.

3n2 = 147

A{-3, 7}

B{-7, 3}

C{-49, 49}

D{-7, 7}

Question

Jewel Myers

Mathematics

18 October, 00:30

How do i solve a quadratic equation like this

Solve.

3n2 = 147

A{-3, 7}

B{-7, 3}

C{-49, 49}

D{-7, 7}

+4

Answers (2)

Know the Answer?

Ansley Jenkins · Answer 1

D{-7, 7}

Dtep-by-step explanation:

3n² = 147

n² = 147/3

n² = 49

n = 7, - 7

Carrot · Answer 2

Option D. {-7, 7}

Step-by-step explanation:

3n^2 = 147

First, divide both side 3

n^2 = 147/3

n^2 = 49

Next, rearrange the variables to one side of the equation as shown below:

n^2 - 49 = 0

n^2 - 7^2 = 0

The above is now difference of two squares. This can be solve by doing the following:

(n - 7) (n + 7) = 0

n - 7 = 0 or n + 7 = 0

n = 7 or n = - 7

How do i solve a quadratic equation like thisSolve.3n2 = 147A{-3, 7}B{-7, 3}C{-49, 49}D{-7, 7}

How do i solve a quadratic equation like this

Solve.

3n2 = 147

A{-3, 7}

B{-7, 3}

C{-49, 49}

D{-7, 7}