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11 November, 22:04

What are the zeros of the polynomial function?

f (x) = x^3 + 2x^2 - x - 2

select each correct answer:

-3

-2

-1

0

1

2

3

+2
Answers (1)
  1. 11 November, 22:20
    0
    -2, - 1 and 1.

    Step-by-step explanation:

    x^3 + 2x^2 - x - 2 = 0

    x^2 (x + 2) - 1 (x + 2) = 0 Note the common factors (x + 2) so we have

    (x^2 - 1) (x + 2) = 0

    (x - 1) (x + 1) (x + 2) = 0 (x^2 - 1 is the difference of 2 squares).

    x = - 2, - 1 and 1.
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