Ask Question
30 July, 04:54

Suppose you just received a shipment of twelve televisions. Two of the televisions are defective. If two televisions are randomly selected, compute the probability that both televisions work. What is the probability at least one of the two televisions does not work?

+1
Answers (1)
  1. 30 July, 05:05
    0
    P (both work) = ((10-3) / 10) * ((10-3-1) / 9) = (7/10) * (6/9) = 42/90

    P (at least one does not work) = 1 - P (both work) = 1 - 42/90 = 48/90 = 24/45.
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “Suppose you just received a shipment of twelve televisions. Two of the televisions are defective. If two televisions are randomly selected, ...” in 📗 Mathematics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers