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27 May, 11:04

What are the real roots of 2x^3-42x-40

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  1. 27 May, 11:11
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    2x^3-42x-40=0

    2x^3-42x=40

    2x (x^2-21) = 40

    a. 2x=40=>x=20

    b. x^2=21+40=>x^2=61=>x = + - (radical (61)
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