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Anabelle
Mathematics
27 May, 11:04
What are the real roots of 2x^3-42x-40
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Aditya Solomon
27 May, 11:11
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2x^3-42x-40=0
2x^3-42x=40
2x (x^2-21) = 40
a. 2x=40=>x=20
b. x^2=21+40=>x^2=61=>x = + - (radical (61)
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