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17 October, 21:36

X varies inversely with y and x = 8 when y = 10, what is the value of y when x=6

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  1. 17 October, 21:37
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    The right answer for the question that is being asked and shown above is that:

    x = k (1/y)

    k = xy

    x1y1 = x2y2

    8*10 = 6y2

    80 = 6y2

    y2 = 40/3

    So the answer is 40/3

    X varies inversely with y and x = 8 when y = 10, what is the value of y when x=6
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