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8 August, 04:34

The area of a playground is 204 yd^2 The width of the playground is 5 yd longer than its length. Find the length and width of the playground.

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Answers (2)
  1. 8 August, 04:51
    0
    12

    Step-by-step explanation:

    Assuming that the shape of the playground is rectangular, we know that the area of a rectangle is length x width.

    Let the length = x

    width = x + 5

    x (x + 5) = 204

    x² + 5x = 204

    x² + 5x - 204 = 0

    (x + 17) (x - 12) = 0

    x = - 17 and x = 12

    However, since x represents the length of the playground, length cannot be negative. The only value possible is x = 12.

    Therefore, the playground has a length of 12 yd and a width of 12 + 5 = 17 yd.
  2. 8 August, 04:57
    0
    length = 17 yd, width = 12 yd
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