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7 October, 07:41

Write the quadratic equation in standard form and then choose the value of "b." (2x - 1) (x + 5) = 0

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  1. 7 October, 07:59
    0
    If we were to foil

    after experieence

    we know

    ax²+bx+c=0

    and

    in form

    (ax+b) (cx+d) = 0

    if we expand it, we get

    acx²+bcx+adx+bd=0

    or

    (ac) x² + (bc+ad) x + (bd) = 0

    compare to

    ax²+bx+c=0

    we notice that the middle terms (x terms) are

    b = (bc+ad)

    so

    in form

    (2x-1) (1x+5)

    b=bc+ad = (-1*1+2*5) = - 1+10=9

    b=9

    or you could just expand it
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