A rectangle's length is 4 feet more than its width. Write a quadratic function

that expresses the rectangle's area in terms of its width.

A. A (W) = w^2 - 4w

B. A (w) = w^2+4w

c. A (w) = w+4

D. A (w) = lw

Question

Zane Villanueva

Mathematics

30 May, 23:24

A rectangle's length is 4 feet more than its width. Write a quadratic function

that expresses the rectangle's area in terms of its width.

A. A (W) = w^2 - 4w

B. A (w) = w^2+4w

c. A (w) = w+4

D. A (w) = lw

+4

Answers (1)

Know the Answer?

Orlando Kaufman · Answer 1

B. A (w) = w∧2+4w

Step-by-step explanation:

Let the width of the rectangle be w.

The length is 4 feet longer than the width = w+4

Area of a rectangle = length * width

A=L*W

= (w+4) * w

Opening the brackets gives the:

A=w²+4w

Therefore the expression for the area in terms of width is A (w) = w∧2+4w

A rectangle's length is 4 feet more than its width. Write a quadratic functionthat expresses the rectangle's area in terms of its width.A. A (W) = w^2 - 4wB. A (w) = w^2+4wc. A (w) = w+4D. A (w) = lw

A rectangle's length is 4 feet more than its width. Write a quadratic function

that expresses the rectangle's area in terms of its width.

A. A (W) = w^2 - 4w

B. A (w) = w^2+4w

c. A (w) = w+4

D. A (w) = lw