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3 July, 02:47

Consider a poisson distribution with an average of 3 customers per minute at the local grocery store. If x=the number of arrivals per minute, find the expected value of x.

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  1. 3 July, 03:09
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    (10b x 3p) (x * b)

    30pb * x * b

    10b / b = x

    x = 3 p = 3

    Step-by-step explanation:

    so x must be 3 and p must be 10 so you area able to expand

    multiple time

    percentages

    mean

    and sample data

    We set the equation so we can calculate the daily average hr and deduct the amount of arrival totals on any one week to show a percentage multiplier of decrease value.

    2) We reset it to show the mean sample data of hrs in a week and the amount of customers totaled for third line, 4th line will show the total x value where the equal number prior will show the mean sample multiplied no of total customers and total range sample to compare with the percentage that would accommodate 3)

    3) Percentage; we take the new p symbol and input the results of 1.

    Where p = 3 = visitors stay >100%

    pb will always show the true minutes as 3 x 10 is 30mins and every 30mins you have 90 customers. x (p * b) then x * b = p/b

    Step 3 would use this set data against percentage of staff rotation.

    x * b - p = - 1 minute

    Just like 2x * p = 1 hr 2x p^2 = 45 = 15 b)

    Percentages staff rotation.

    2x * p^2 * b ( - x * p * p) = 2x p^2

    = 6 x 9 x 3

    = 153/45 = 3.4

    3.4 - x = 2/5

    2/5 x p x p = 2/5 x 10 x 10 = 40%
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