In a first-order decomposition reaction. 52.3% of a compound decomposes in 8.6 min. How long (in min) does it take for 80.3% of the compound to decompose? Enter to 2 decimal places.

Question

Lilah Petty

Mathematics

16 August, 20:15

In a first-order decomposition reaction. 52.3% of a compound decomposes in 8.6 min. How long (in min) does it take for 80.3% of the compound to decompose? Enter to 2 decimal places.

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Answers (1)

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Killian Horne · Answer 1

13.20 min

Step-by-step explanation:

Rate of the reaction is a measure of the rate of decomposition of the compound.

Rate (R) = Concentration (C) : time (t)

C1/t1 = C2/t2

C1 = 52.3% = 0.523

t1 = 8.6 min

C2 = 80.3% = 0.803

t2 = C2t1/C1 = 0.803*8.6/0.523 = 13.20 min (to 2 decimal places)