The width of the mirror is 4/9 it's lenght the area of the mirror is 576 sq in. what are the dimension s of the mirror

Suppose the length is x and the width is 4/9x and the whole mirror is 4/9x*x=576

or 4/9 (x^2) = 576 first divide both sides by 4/9

x^2=16 solve for x

x=4

Area = L (ength) x W (idth)

W = 4/9L

You just need to plug in the numbers into the area formula and solve

576 = L * 4/9L

576 = 4/9L² (combining the two variables since they are the same)

(9/4) 576 = 4/9L² (9/4) (isolating L²)

1296 = L²

√1296 = √L² (isolating L by removing the square. √ is the opposite of ²)

36 = L

Since we know 36 is L now we need to find W (using the formula we made)

W = 4/9L

W = 4/9 (36)

W=16

The dimensions of the mirror are 36 in. x 16 in.