The area of a rectangle is 14 m2, and the length of the rectangle is 3 m less than double the width. find the dimensions of the rectangle.

Width = 3.5, length = 4

Let's make a few equations to summarize what we know.:

a = 14

l = 2w - 3

a = wl

Now let's substitute the expression for l into the expression for area and solve.

a = w (2w - 3)

a = 2w^2 - 3w

14 = 2w^2 - 3w

0 = 2w^2 - 3w - 14

which factors into

(2w - 7) (w + 2)

Solving for w

2w - 7 = 0

2w = 7

w = 3.5

w+2 = 0

w = - 2

So w can be either 3.5 or - 2. Since a negative width doesn't make sense, w = 3.5

Let's verify

w = 3.5

l = 2w - 3

l = 2*3.5 - 3

l = 7 - 3

l = 4

a = wl

a = 3.5 * 4

a = 14

So the width is 3.5 and the length is 4.