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Zachariah Lucero
Mathematics
Yesterday, 23:48
Evaluate log base 12 of y^2, given log base 12=16
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Tommy Nolan
Yesterday, 23:50
0
y = 12^8
Step-by-step explanation:
Log base 12, y^2 = 16
y2 = 12^16
y = sqrt (12^16) = (12^16) ^1/2
y = 12^8
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