A container has 130 gallons of water and is being filled at a rate of 1/4 gallon each second. Another container has 200 gallons of water and is draining at a rate of 1/3 gallon each second. When will the 2 containers have the same amount of water?

Question

Kieran Montes

Mathematics

13 August, 20:15

A container has 130 gallons of water and is being filled at a rate of 1/4 gallon each second. Another container has 200 gallons of water and is draining at a rate of 1/3 gallon each second. When will the 2 containers have the same amount of water?

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Answers (1)

Know the Answer?

Bridger Carey · Answer 1

120 seconds

Step-by-step explanation:

To solve this question you have to make equation of both gallon.

Gallon 1 have 130 gallons of water at the start and filled by 1/4 gallon each second. If x equal to the time in seconds, the equation of gallon 1 volume will be:

g1 = 130 + 1/4x

Gallon 1 have 200 gallons of water at the start and drained by 1 / 3 gallon each second, the equation of gallon 2 volume:

g2 = 200 - 1/3x

When gallon 1 volume equal to gallon 2, it mean g1=g2

g1 = g2

130 + 1/4x = 200 - 1/3x

130 - 200 = - 1/3x - 1/4x

-70 = - 4/12x - 3/12x

-7/12x = - 70

7/12x = 70

x = 70*12/7

x = 120