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19 January, 11:05

The rectangle below has an area of 7b^2+14b square meters. The width of the rectangle (in meters) is equal to to the greatest common monomial factor of 7b^2 and 14b. What is the length and width of the rectangle?

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  1. 19 January, 11:22
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    L = b + 2.

    W = 7b

    Step-by-step explanation:

    Factoring 7b^2 and 14b, we get 7b (b + 2). The greatest common monomial factor here is 7b. This is the width of the rectangle in question.

    The area of the rectangle is 7b^2+14b.

    Obtain the length of the rectangle by dividing 7b^2+14b by 7b:

    L = b + 2.

    W = 7b
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