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31 December, 00:50

Find the horizontal or oblique asymptote of F (x) = - 2x^2+3x+6/x+2

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  1. 31 December, 01:03
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    F (x) = - 2 (x^2) + 3x + (6/x) + 2

    fx=2x+3x + (2*3/x) + 2

    fx={-x*2 (x^2) + x (3x) + (2+3) + x*2) / x

    result:

    fx={-2 (x^3) + 3 (x^2) = 2x+6 / (x^2)
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