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19 March, 05:06

What are the solutions for x when y is equal to 0 in the quadratic function y=x^2-8x

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  1. 19 March, 05:17
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    I would use the quadratic formula for this:

    x = - b ± √b² - 4ac over 2a

    x = 8 ± √64 - 4 (1) (0) over 2 (1)

    x = 8 ± √64 over 2

    x = 8 ± 8 over 2 [simplify]

    x = 4 ± 4

    x1 = 4 + 4 x2 = 4 - 4

    x1 = 8 x2 = 0

    Thus, the solutions for x would be 0 and 8.
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