There are 5 red marbles, 15 blue marbles, and 5 green marbles in a bag. You reach in and randomly draw a marble, replace it, and draw another marble. What is the probability that the first will be red and the second will be blue?

80%

20%

12%

8%

Question

Wyatt

Mathematics

8 July, 20:58

There are 5 red marbles, 15 blue marbles, and 5 green marbles in a bag. You reach in and randomly draw a marble, replace it, and draw another marble. What is the probability that the first will be red and the second will be blue?

80%

20%

12%

8%

+4

Answers (1)

Know the Answer?

Toby Charles · Answer 1

I would estimate around 8% or 12% is the answer. Red Marbles are a small percentage and the chance it will be picked instead of something else is rare however blue marbles are the most common and chance one will be picked is fairly high.

There are 5 red marbles, 15 blue marbles, and 5 green marbles in a bag. You reach in and randomly draw a marble, replace it, and draw another marble. What is the probability that the first will be red and the second will be blue?80%20%12%8%

There are 5 red marbles, 15 blue marbles, and 5 green marbles in a bag. You reach in and randomly draw a marble, replace it, and draw another marble. What is the probability that the first will be red and the second will be blue?

80%

20%

12%

8%