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A dairy wishes to mix together 1,000 pints of milk that contains 8% butterfat. if the mixture is to be made from milk containing 5% butterfat, and cream containing 20% butterfat, how many pints of each is needed?

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Answers (2)
  1. 29 July, 23:05
    0
    We can write the question as a mathematical formula as follows:

    1000 * 0.08 = m * 0.05 + c * 0.2

    1000 = m + c

    where m are pints of milk and c are pints of cream

    So solving the first equation with m = 1000 - c

    1000*0.08 = (1000-c) * 0.05 + c*0.2

    80 = 50 - 0.05c + 0.2c

    80-50 = (0.2-0.05) * c

    30 = 0.15*c

    c = 30/0.15

    c = 200

    m = 1000-200 = 800

    So the dairy needs 800 pints of milk and 200 pints of cream
  2. 29 July, 23:15
    0
    x = pints of 5% butterfat

    y = pints of 20% butterfat

    x + y = 1000

    5x + 20y = 8*1000

    put the system of linear equations into standard form

    x + y = 1000

    5x + 20y = 8000

    Solving:

    1000*0.08 = (1000-c) * 0.05 + c*0.2

    80 = 50 - 0.05c + 0.2c

    80-50 = (0.2-0.05) * c

    30 = 0.15*c

    c = 30/0.15

    c = 200

    m = 1000-200 = 800

    Therefore,

    x = pints of 5% butterfat = 800

    y = pints of 20% butterfat = 200
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