Ask Question
30 June, 03:42

Anthony Papantonis, owner of Nauset Construction, is bidding on two projects, A and B. The probability that he wins project A is 0.50 and the probability that he wins project B is 0.80. Winning Project A and winning Project B are independent events.

a. What is the probability that he wins project A or project B?

b. What is the probability that he does not win either project?

+5
Answers (1)
  1. 30 June, 03:48
    0
    a) the probability of winning A and B is 0.4 (40%)

    b) the probability of not winning either project is 0.1 (10%)

    Step-by-step explanation:

    if 2 events are independent then

    P (A∩B) = P (A) * P (B)

    where

    P (A) = probability of winning project A

    P (B) = probability of winning project B

    P (A∩B) = probability of winning projects A and B

    replacing values

    P (A∩B) = P (A) * P (B) = 0.50 * 0.8 = 0.4

    b) since

    P (A∪B) = P (A) + P (B) - P (A∩B) = 0.50 + 0.8 - 0.4 = 0.9

    where

    P (A∪B) = probability of winning A or B

    therefore

    probability of not winning either project = 1 - P (A∪B) = 1 - 0.9 = 0.1 (10%)
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “Anthony Papantonis, owner of Nauset Construction, is bidding on two projects, A and B. The probability that he wins project A is 0.50 and ...” in 📗 Mathematics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers