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29 March, 14:25

K^3-27 in difference of cubes

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  1. 29 March, 14:42
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    (k - 3) (k^2 + 3k + 9)

    Step-by-step explanation:

    Base equation:

    (k^3 - 3^3)

    The first bracket will be a - b, second will be:

    a^2 + ab + b^2

    (k - 3) (k^2 + 3k + 9)
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