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Braylon Farley
Mathematics
29 March, 14:25
K^3-27 in difference of cubes
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Hebert
29 March, 14:42
0
(k - 3) (k^2 + 3k + 9)
Step-by-step explanation:
Base equation:
(k^3 - 3^3)
The first bracket will be a - b, second will be:
a^2 + ab + b^2
(k - 3) (k^2 + 3k + 9)
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