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30 November, 14:34

Rounded to the nearest hundredth, what is the positive solution to the quadratic equation 0=2x2+3x-8?

Quadratic formula: x = StartFraction negative b plus or minus StartRoot b squared minus 4 a c EndRoot Over 2 a EndFraction

A. 1.39

B. 2.00

C. 2.89

D. 3.50

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Answers (2)
  1. 30 November, 14:39
    0
    its a. 1.39
  2. 30 November, 14:49
    0
    Step-by-step explanation:

    The given quadratic equation is

    2x^2+3x-8 = 0

    To find the roots of the equation. We will apply the general formula for quadratic equations

    x = - b ± √b^2 - 4ac]/2a

    from the equation,

    a = 2

    b = 3

    c = - 8

    It becomes

    x = [ - 3 ± √3^2 - 4 (2 * - 8) ]/2*2

    x = - 3 ± √9 - 4 ( - 16) ]/2*2

    x = [ - 3 ± √9 + 64]/2*2

    x = [ - 3 ± √73]/4

    x = [ - 3 ± 8.544]/4

    x = (-3 + 8.544) / 4 or x = (-3 - 8.544) / 4

    x = 5.544/4 or - 11.544/4

    x = 1.386 or x = - 2.886

    The positive solution is 1.39 rounded up to the nearest hundredth
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