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21 February, 05:30

Which equation has the same solution 2x²+16x-10=0

a. (x+4) ² = - 3

b. (x+4) ² = - 11

C ... (x+4) ² = 13

d. (x+4) ² = 21

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  1. 21 February, 05:52
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    2x²+16x-10=0

    is equivalent to: (divide by two)

    x²+8x-5=0

    The answer is d. (x+4) ² = 21

    Because,

    (x+4) ² = 21

    x² + 8x + 16 = 21

    x² + 8x + 16 - 21 = 0

    x² + 8x - 5 = 0
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