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Given the recursive function f (n) = f (n - 1) - 3; f (1) = 9, what would be the first three terms of the sequence?

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  1. 5 July, 14:56
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    The first three terms of sequence are 9, 6, 3

    Solution:

    Given the recursive function f (n) = f (n - 1) - 3

    Where f (1) = 9

    To find: First three terms of sequence

    Substitute n = 2, n = 3 and n = 4 in given recursive function

    When n = 2

    f (n) = f (n - 1) - 3

    f (2) = f (2 - 1) - 3

    f (2) = f (1) - 3

    f (2) = 9 - 3 = 6

    f (2) = 6

    Thus second term is 6

    When n = 3

    f (3) = f (3 - 1) - 3

    f (3) = f (2) - 3

    f (3) = 6 - 3 = 3

    f (3) = 3

    Thus the third term is 3

    When n = 4

    f (4) = f (4 - 1) - 3

    f (4) = f (3) - 3

    f (4) = 3 - 3

    f (4) = 0

    Thus the fourth term is 0

    Thus first three terms of sequence are 9, 6, 3
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