Write the polynomial in standard form and identify the x-intercept, as well as the zeros for

f (x) = (x - 3i) (x - 3i)

Well, ok, the x intercepts aer where the function equals 0

also

if the x intercepts are r1 and r2 then the factored form of the function is

f (x) = a (x-r1) (x-r2) where a is a constant

well, we have it already in that form

f (x) = (x-3i) (x-3i)

the x intercept is at x=3i

standard form requires expansion

we expand to get

f (x) = x²-6i-9