If the nth term is 299find the value of n while arthmetic sequence is 13,24,35 ...

Aritmetic

an=a1+d (n-1)

a1=first term

d=common differnce

common differnce is a term minus pervious term

24-13=11

d=11

a1=first term=13

13+11 (n-1)

the nth term

299=13+11 (n-1)

solve

distribute

299=13+11n-11

299=11n+2

minus 2 both sides

297=11n

divide both sides by 11

27=n

it is the 27th term