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29 September, 23:30

Determine whether ln (n / (3n+1)) diverges or converges.

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  1. 29 September, 23:50
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    To determine this we need to find limit when n-> infinity

    lim ln (n / (3n+1)) = lim ln (n / (n * (3+1/n))

    we can shorten n

    after putting that n - > infinity we get that it converges to 1/3
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