The ideal gas law states that the volume, v, of a gas in liters varies directly with the amount of the gas in moles, n, and the absolute temperature in Kelvin, T, and varies inversely with the pressure, P, of the gas. Two moles of a gas has a volume of 35.424 L at 270 Kelvin when P = 1.25 atm. What is the volume of 3 moles of a gas at 280 Kelvin when P = 1.5 atm?

A. 11.48 L

B. 27.33 L

C. 45.92 L

D. 103.32 L

Question

Cole Snyder

Mathematics

21 September, 10:06

The ideal gas law states that the volume, v, of a gas in liters varies directly with the amount of the gas in moles, n, and the absolute temperature in Kelvin, T, and varies inversely with the pressure, P, of the gas. Two moles of a gas has a volume of 35.424 L at 270 Kelvin when P = 1.25 atm. What is the volume of 3 moles of a gas at 280 Kelvin when P = 1.5 atm?

A. 11.48 L

B. 27.33 L

C. 45.92 L

D. 103.32 L

+4

Answers (1)

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Cesar · Answer 1

It is stated that:

The ideal gas law states that the volume, v, of a gas in liters varies directly with the amount of the gas in moles, n, and the absolute temperature in Kelvin, T, and varies inversely with the pressure, P, of the gas.

So, we will have the formula V=nRT/P

V = nRT/P

= (3mol) (0.082057 Latm/Kmol) (280K)

1.5

= 45.9536L