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11 July, 19:55

The perimeter of a rectangle is 56 feet. Describe the the possible lengths of a side if the area of the rectangle is not to exceed 132 square ft

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  1. 11 July, 20:07
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    P = 2 (L + W)

    56 = 2 (L + W)

    56/2 = L + W

    28 = L + W ... L = 28 - W

    A = L * W

    132 = W (28 - W)

    132 = - W^2 + 28W

    W^2 - 28W + 132 = 0

    (W - 6) (W - 22) = 0

    W - 6 = 0 L = 28 - W

    W = 6 L = 28 - 6

    L = 22

    W - 22 = 0 L = 28 - W

    W = 22 L = 28 - 22

    L = 6

    not sure which (length or width) ... one of them is 6 ft and the other is 22 ft
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