Ask Question
20 May, 05:09

The population of anywhere USA was estimated to be 568,600 in 2002, with an expected increase of 4.8% per year. At the rate of increase given what is the expected population in 2003 round your answer to nearest integer

+1
Answers (1)
  1. 20 May, 05:34
    0
    595892

    Step-by-step explanation:

    Population in 2002 was estimated to be 568,600.

    Expected increase of 4.8% per year.

    That Is 4.8% / 100%x 568,600

    0.48 x 568600

    27292.8

    27293

    In 2003 the population at an increased rate of 4.8% will be

    27293 + 568600

    = 595892
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “The population of anywhere USA was estimated to be 568,600 in 2002, with an expected increase of 4.8% per year. At the rate of increase ...” in 📗 Mathematics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers