A ball is thrown straight up from the top of a tower that is 280 ft high with an initial velocity of 48 ft/s. the height of the object can be modeled by the equation s (t) = - 16t^2+48t+280. in two or more sentences explain how to determine the time the ball is lower than the building in interval notation.

Question

Bowman

Mathematics

5 November, 19:54

A ball is thrown straight up from the top of a tower that is 280 ft high with an initial velocity of 48 ft/s. the height of the object can be modeled by the equation s (t) = - 16t^2+48t+280. in two or more sentences explain how to determine the time the ball is lower than the building in interval notation.

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Alma Conway · Answer 1

First find the time that the ball is level with the top of the building on its descent. You can do this by solving 280 = - 16^2 + 48t + 280 for t. This gives t = 3 seconds.

Then when the ball reaches the ground the time t is obtained by solving 0 = - 16t^2 + 48t + 280 This gives t = 5.94 seconds.

Answer in interval notation is (3, 5.94].