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27 July, 19:56

Tan x = sin x/cos x. Therefore, tan (90-A) =

A) 1/tan (90-A)

B) 1/sin A

C) 1/cos (90-A)

D) 1/tanA

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Answers (1)
  1. 27 July, 20:10
    0
    Sin (90-A) = cos A

    cos (90-A) = sin A

    Therefore,

    tan (90-A) = sin (90-A) / cos (90-A) = (cos A) / (sin A) = 1 / (tan A)
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