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30 December, 03:47

3x^3 - 2y^-6x^2y^2+xy for x=2/3 and y=1/2

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Answers (1)
  1. 30 December, 03:50
    0
    -13

    Step-by-step explanation:

    3x^3 - 2y^-6x^2y^2+xy

    x=2/3 and y=1/2

    Solve:

    3x^3 - 2y^-6x^2y^2+xy

    Put value of x and y in this equation

    = 3 (2/3) ^3 - 2 (1/2) ^-6 (2/3) ^2 (1/2) ^2 + (2/3) (1/2)

    = - 13
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