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12 April, 22:05

What is the solution to the system of equations below? y = negative one-fourth x + 2 and 3 y = negative three-fourths x minus 6 no solution infinitely many solutions (-16, 6) (-16, - 2)

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  1. 12 April, 22:12
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    no solution

    Step-by-step explanation:

    Suppose the system equations are:

    y = (-1/4) x + 2 (1)

    3y = (-3/4) x - 6 (2)

    If we multiply equation (1) by 3:

    3y = (-3/4) x + 6 (1)

    3y = (-3/4) x - 6 (2)

    then subtract it from equation (2):

    0y = 0x - 12

    0 = - 12

    This is not possible, therefore, the system equation has no solution
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