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21 February, 21:40

According to Masterfoods, the company that manufactures M&M's, 12% of peanut M&M's are brown, 15% are yellow, 12% are red, 23% are blue, 23% are orange and 15% are green. (Round your answers to 4 decimal places where possible) Compute the probability that a randomly selected peanut M&M is not orange.

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  1. 21 February, 22:10
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    0.77 or 77%

    Step-by-step explanation:

    Given:

    Percentage of brown peanuts = 12%

    Percentage of yellow peanuts = 15%

    Percentage of red peanuts = 12%

    Percentage of blue peanuts = 23%

    Percentage of orange peanuts = 23%

    Percentage of green peanuts = 15%

    Total = 0.12 + 0.15 + 0.12 + 0.23 + 0.23 + 0.15 = 1

    Probability that a randomly selected peanut M&M is not orange:

    P (orange) ' = 1 - P (orange)

    Where,

    P (orange) = 23% = 0.23

    Thus,

    P (orange) ' = 1 - 0.23

    P (orange) ' = 0.77

    Probability that a randomly selected peanut is not orange = 0.77
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