Eliminate the parameter.

x = 3 cos t, y = 3 sin t

x^2+y^2 = 3^2

Step-by-step explanation:

We need to eliminate the parameter t

Given:

x = 3 cos t

y = 3 sin t

Squaring the above both equations

(x) ^2 = (3 cos t) ^2

(y) ^2 = (3 sin t) ^2

x^2 = 3^2 cos^2t

y^2=3^2 sin^2t

Now adding both equations

x^2+y^2=3^2 cos^2t+3^2 sin^2t

Taking 3^2 common

x^2+y^2=3^2 (cos^2t+sin^2t)

We know that cos^2t+sin^2t = 1

so, putting the value

x^2+y^2=3^2 (1)

x^2+y^2 = 3^2

Hence the parameter t is eliminated.