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29 April, 11:59

Find one value of x that is a solution to the equation:

(x - 2) ^2 - 6 (x - 2) + 5 = 0

x =

+4
Answers (1)
  1. 29 April, 12:22
    0
    3 or 7

    Let (x-2) be a

    a^2 - 6a + 5 = 0

    (a-5) (a-1) = 0

    a=5 or a=1

    x-2=5 or x-2=1

    x=7 or x=3
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