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7 March, 18:18

If (x/100-1) (x/100+1) = kx^2-1 k=

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  1. 7 March, 18:43
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    (x/100-1) (x/100+1) = kx^2-1

    (x/100-1) (x/100+1) = (x/100) ^2 - 1^2 because it's a difference of squares ((a-b) (a+b) = a^2-ab+ab-b^2 = a^2 - b^2):

    (x/100) ^2 - 1^2=kx^2 - 1

    (x/100) ^2 - 1=kx^2 - 1

    (x/100) ^2=kx^2

    (x^2) / (100^2) = kx^2

    1 / (100^2) = k

    1/10000=k

    k=0.0001
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