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30 August, 03:23

Given the perimeter of a rectangle is 96 meter and the length is twice the width, find the dimensions. Solve algebraically.

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Answers (2)
  1. 30 August, 03:34
    0
    96 + 96

    2 (96x2) is the answer
  2. 30 August, 03:50
    0
    96/6=16

    16+32+16+32=96

    The length would be 32 while the width would be 16.
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