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3 December, 00:13

What number comes next 16, 06, 68, 88,

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  1. 3 December, 00:40
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    So the given series is "16, 06, 68, 88, __"

    Count all the cyclical opening in each of these numbers. For example in 16, there is a one cyclical loop present in it (the one in 6), similarly in 06 it is two (one in zero and one in 6), going ahead, in 68 it is 3 (one in 6 and two in 8).

    From here on things become simple: hence, the cyclical figures in these equations written down becomes 1,2,3,4,_,3.

    Let's now try solving the above sequence, going by the logical reasoning the only number that can fill in the gap should be 4.
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