A pork roast22 was taken out of a hardwood smoker when its internal temperature had reached 180◦F and it was allowed to rest in a 75◦F house for 20 minutes after which its internal temperature had dropped to 170◦F. Assuming that the temperature of the roast follows Newton's Law of Cooling (Equation 6.6),

(a) Express the temperature T (in ◦F) as a function of time t (in minutes). (b) Find the time at which the roast would have dropped to 140◦F had it not been carved and eaten.

Question

20 December, 12:40

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Kayla Fitzpatrick · Answer 1

A : T (t) = 75 + 105e - 0.005005t

B: The roast would have cooled to 140◦F in about 95 minutes.

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