An object is thrown upward at a speed of 121 feet per second by a machine from a height of 8 feet off the ground. The height h of the object after t seconds can be found using the equation h = - 16t^2+121 t+8

When will the height be 17 feet?

When will the object reach the ground?

Question

Essence Irwin

Mathematics

3 April, 09:36

An object is thrown upward at a speed of 121 feet per second by a machine from a height of 8 feet off the ground. The height h of the object after t seconds can be found using the equation h = - 16t^2+121 t+8

When will the height be 17 feet?

When will the object reach the ground?

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Answers (1)

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Pumpkin · Answer 1

17=-16t^2+121t+8

16t^2-121t+9=0

this is a quadratic.

it solves to 7.487seconds and 0.075 seconds.

0=-16t^2+121t+8

16t^2-121t-8=0

this solves to 7.628 and - 0.066. obviously the time cant be negative so the only real answer is 7.628 seconds

An object is thrown upward at a speed of 121 feet per second by a machine from a height of 8 feet off the ground. The height h of the object after t seconds can be found using the equation h = - 16t^2+121 t+8When will the height be 17 feet?When will the object reach the ground?

An object is thrown upward at a speed of 121 feet per second by a machine from a height of 8 feet off the ground. The height h of the object after t seconds can be found using the equation h = - 16t^2+121 t+8

When will the height be 17 feet?

When will the object reach the ground?