Four times the lesser of two consecutive even integers is 12 less than twice the greater number. Find the integers.

The numbers are: 2n and (2n+2)

we can suggest this equation:

4 (2n) = 2 (2n+2) - 12

We compute this equation:

8n=4n+4-12

8n-4n=-8

4n=-8

n=-8/4

n=-2

we compute the numbers:

2n=2 (-2) = - 4

2n+2=-4+2=-2

answer: the numbers are - 4 and - 2.